Tensor product of modules
Like the free group and the free module, the tensor product of two -modules is another construction satisfying an interesting universal property, but with a richer structure than these two. Namely, it is (when possible) an
-module, denoted
such that every bilinear map from
to another
-module uniquely factors through
Given a unitary ring a right
-module
and a left
-module
we will first construct the tensor products of
and
as an abelian group. We can then, when possible, give it a module structure.
Definition: The tensor product of and
over the ring
, noted
or
is the quotient of the free
-module (or equivalently the free abelian group) over
by the subgroup generated by all elements of the form (
)
;
;
for any and
Elements of
are called tensors and the cosets, denoted
, represented by
are called simple tensors.
Note the similarity between this definition and that of the free group or free module: we took all couples in and quotiented out by the minimal relations giving us the most general module possessing the properties we wanted, namely
;
;
for all (Note the similarity between these and the definition of a bilinear map.) It is easy to see that every tensor is a finite sum of simple tensors and that
is an abelian group (for addition of tensors).
Definition: For and
two rings, an
–bimodule is a module which is a left
-module and a right
-module.
Suppose is an
-bimodule, then
can be given a left
-module structure by letting
An important remark is that for a commutative ring and a
-module
letting the left and right actions of
on
be equal by
gives
a natural
-bimodule structure and thus gives
a left
-module structure. To simplify matters, I will therefore assume in the rest of this post that
is commutative and that
has this natural bimodule structure.
Theorem (Universal property): Let
be a commutative and unitary ring,
and
three
-modules and
a bilinear map. Then there exists a unique
-module homomorphism
such that
ie such that this diagram commutes :
(Where )
Proof: By the universal property of free abelian groups (identifying abelian groups with -modules) the map
defines a unique
-module homomorphism
from the free
-module on
to
such that
Since
is bilinear,
sends every element of the form (
) to
so
contains the subgroup by which we quotiented
to obtain
at the beginning of this post. Letting
be
thus gives us a well-defined group homomorphism
such that
Moreover, we have
so is also an
-module homomorphism. Since
generates
(every tensor is a finite sum of simple tensors) we can conclude by linearity that
is the unique
-module homomorphism satisfying these properties.
QED
Note that for every -module homomorphism
the map
is an
-bilinear map. So by the last theorem, there is a bijection between the sets
and
Reference: D. S. Dummit, R. M. Foote, Abstract Algebra, 3rd ed.
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